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the elegance is the slowness, and the clock is right by the wrong road

Issue #200, 2026-09-13. Constructed, Duel (485). Rules version 2026-07-16, opened in data/Riftbound-Core-Rules-2026-07-16.txt; card text verbatim from data/corpus_flat.txt. Read the unopposed clock first for what a baseline is.

Subject: shen-sentinel-time-warp-chain. With the turn clock's engine-output pricing landed, four of eighty finishers pay later than the CONTESTED curve — the board a finisher is actually for — and three of those four are one closure, the nineteen-card gemdragon-henge-vi-blind-fury board. This is the fourth, and the only other one. It is also, card for card, one of the tidiest things in the catalogue.


1. What it does

Three cards. VEN-138 Shen, Leader of the Kinkou Order (Order, E6 + 2 Power) and UNL-087 Blue Sentinel (Mind, E4 + 1 Power) stand at one battlefield you control with nothing else there, plus two copies of OGN-122 Time Warp (Mind, E10 + 4 Power).

Each Beginning Phase you Hold: 1 point from the Score (469.2, capped once per battlefield per turn by 470), and Shen's trigger — "if there is exactly one other unit you control here" — doubled by the Sentinel into two ability Gains. Three points a turn. A Time Warp on each of the first two turns means the opponent never acts, and the third Hold crosses eight.

2. Why it is elegant, and the entry proves this part itself

The Time Warps look like twenty Energy and eight Power of extra cost. They are not. The entry's own step 1 says so — "No third card is needed — the rune economy pays for the Time Warps by itself" — and the ledger holds:

E12 + 4 Power against a Time Warp at E10 + 4 Power, with two Energy to spare. The extra turns are free. That is a genuinely good piece of design and it is why the entry needs no discount package.

3. So why does it land on turn ten

Because self-funding needs twelve runes, and twelve runes is turn eight.

161.2.a fixes the Rune Deck at exactly twelve. 315.3.b channels two a turn. And 161.2.b sends every rune spent on Power to the Rune Deck, taking it off the board. The deployment is Shen at two Power and the Sentinel at one — three runes gone — so the board count is min(12, 2T − 3):

turnrunes on board
T34 — Shen lands, two Power paid
T45 — the Sentinel lands, one Power paid
T57
T69
T711
T812

So the first Hold that can also cast a Time Warp is T8. Then T8 for three points, T9 for six, T10 for nine, and 194.2 wins it in the cleanup. Turn ten, against a mind/order unopposed baseline of T6 and a contested curve of T9.

The design that makes the Time Warps free is the design that makes the line slow. Shen's two Order Power and the Sentinel's one are what buy the doubling, and those same three Power are three runes that have to be channelled back before the engine can pay for itself.

4. The instrument agrees and its reasoning does not

npm run adversarial -- --turns puts this row at T10 as well. It gets there by summing both Time Warps into the deployment — E30 and 11 Power across four cards — which is precisely the reading the entry's own step 1 refutes.

Right answer, wrong road. The clock cannot see the twelve-rune floor, and it happens to charge a cost that takes about the same number of turns. Nothing distinguishes the two except a hand walk.

That is not a defect to fix, and the reason is worth stating because it argues for a decision this project already made. CLAUDE.md records that treating spells as cast-on-the-finishing-turn rather than deployed was tried and rejected, because it sends Time-Warp chains to Infinity. This row adds a second, independent argument: that change would make this row faster, and therefore wrong, because it would remove the wrong reason while leaving the real constraint — the rune floor — unmodelled. A number that is right for the wrong reason gets worse when you fix only the reason.

5. Breaks to

6. Verdict

Nothing here is badly built. It is slow because of an interaction between two things that are each correct: the Sentinel doubles the Hold, and Power costs runes. The first is what makes the Time Warps free; the second is what delays them to turn eight.

Whether that matters depends on the board, as always. Against the unopposed curve it is four turns late and irrelevant, because a player holding both battlefields has already won. Against the contested curve it is one turn late — and one turn late is a real verdict rather than a condemnation, since the contested curve's eighth point on T9 is a baseline and not a plan.

The constructive lead, not yet catalogued. This is a mind/order line, and mind/order is the one identity that prints an infinite-Energy engine. Measured: the union of this entry's cards with lux-infinite-energy is two domains and therefore legal under 103.1.b, this entry declares needs: [], no twin exists on its card set, and sixteen entries already declare needs: infinite-energy. The loop-financed twin this project uses elsewhere — identical cards, needs on one row so the matcher can route a loop into the window, both rows cross-referencing — is legal here and absent.

And the objection belongs with the lead — but it is smaller than I first wrote it, and the correction is the useful half. A Lux shell has to empty a 39-card Main Deck, and the setup nobody prices shows there are two routes to that. I attached the draw route's price — roughly twenty-four slots of net-positive draw — as the reason four more cards might not fit. That is the wrong route to quote here. The cheapest emptier is VEN-165 Shadow Temple, a battlefield, and 103.4 keeps battlefields out of the Main Deck's forty entirely, so on the Temple route the emptying costs no deck slots at all. This line needs no particular battlefield, so unlike grand-plaza-loop-time-warp it can simply bring the Temple — and room is not the problem.

What a walker should check instead is the interaction the Temple creates, which is sharper and which I am not going to settle from outside data/combos.json: the Temple's burn carries no "may", so once the deck is empty every Hold is a [Burn 3] into an empty deck, which 431.1.b turns into a Burn Out — and 431.2.c hands an opponent a point each time. A three-Hold chain would be giving away three points while taking nine, and 194.2 asks for "more points than any other player". That is an arithmetic question about one board, which is exactly what a walk is for.